What is expand (2x-4)/((x+1)(x+3)) ?

The solution to expand (2x-4)/((x+1)(x+3)) is (2x-4)/(x^2+4x+3)

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expand (2x-4)/((x+1)(x+3))

expand

\frac{2 x - 4}{( x + 1 ) ( x + 3 )}

\frac{2 x - 4}{x ^{2} + 4 x + 3}

Solution steps

\frac{2 x - 4}{( x + 1 ) ( x + 3 )}

Expand

(x + 1) (x + 3) : x^{2} + 4 x + 3

= \frac{2 x - 4}{x ^{2} + 4 x + 3}

2 x - 1 (4 x + 5 + x - 1)

\frac{p ( 60 - p )}{2}

\frac{d}{d u} ((x (u, t)) (t^{2} + 5 t))

(ln (x) - 1)^{3}

\frac{d ^{2}}{d x ^{2}} ((y) (6 x - 3))

What is expand (2x-4)/((x+1)(x+3)) ?
The solution to expand (2x-4)/((x+1)(x+3)) is (2x-4)/(x^2+4x+3)