What is expand ((x^2+3)^3)/3 ?

The solution to expand ((x^2+3)^3)/3 is (x^6)/3+3x^4+9x^2+9

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expand ((x^2+3)^3)/3

expand

\frac{( x ^{2} + 3 ) ^{3}}{3}

\frac{x ^{6}}{3} + 3 x^{4} + 9 x^{2} + 9

Solution steps

\frac{( x ^{2} + 3 ) ^{3}}{3}

(x^{2} + 3)^{3} = x^{6} + 9 x^{4} + 27 x^{2} + 27

= \frac{x ^{6} + 9 x ^{4} + 27 x ^{2} + 27}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{6} + 9 x ^{4} + 27 x ^{2} + 27}{3} = \frac{x ^{6}}{3} + \frac{9 x ^{4}}{3} + \frac{27 x ^{2}}{3} + \frac{27}{3}

= \frac{x ^{6}}{3} + \frac{9 x ^{4}}{3} + \frac{27 x ^{2}}{3} + \frac{27}{3}

Divide the numbers:

\frac{9}{3} = 3

= \frac{x ^{6}}{3} + 3 x^{4} + \frac{27 x ^{2}}{3} + \frac{27}{3}

Divide the numbers:

\frac{27}{3} = 9

= \frac{x ^{6}}{3} + 3 x^{4} + 9 x^{2} + 9

\frac{1}{( 4 - s ) ^{2}}

(A x^{2} + B x + C) e^{x}

(2 - x - 3) (x - 1 + 2)

\frac{1 - t}{( 1 - t ( 1 - x ) ) ^{2}}

c u r l (x^{2} y, yz, x - z)

What is expand ((x^2+3)^3)/3 ?
The solution to expand ((x^2+3)^3)/3 is (x^6)/3+3x^4+9x^2+9