What is expand (λ(λ-1)(λ-2)(λ-3))/(24) ?

The solution to expand (λ(λ-1)(λ-2)(λ-3))/(24) is (λ^4}{24}-(λ^3)/4+\frac{11λ^2)/(24)-λ/4

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expand (λ(λ-1)(λ-2)(λ-3))/(24)

expand

\frac{λ ( λ - 1 ) ( λ - 2 ) ( λ - 3 )}{24}

\frac{λ ^{4}}{24} - \frac{λ ^{3}}{4} + \frac{11 λ ^{2}}{24} - \frac{λ}{4}

Solution steps

\frac{λ ( λ - 1 ) ( λ - 2 ) ( λ - 3 )}{24}

Expand

λ (λ - 1) (λ - 2) (λ - 3) : λ^{4} - 6 λ^{3} + 11 λ^{2} - 6 λ

= \frac{λ ^{4} - 6 λ ^{3} + 11 λ ^{2} - 6 λ}{24}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{λ ^{4} - 6 λ ^{3} + 11 λ ^{2} - 6 λ}{24} = \frac{λ ^{4}}{24} - \frac{6 λ ^{3}}{24} + \frac{11 λ ^{2}}{24} - \frac{6 λ}{24}

= \frac{λ ^{4}}{24} - \frac{6 λ ^{3}}{24} + \frac{11 λ ^{2}}{24} - \frac{6 λ}{24}

Cancel

\frac{6 λ ^{3}}{24} : \frac{λ ^{3}}{4}

= \frac{λ ^{4}}{24} - \frac{λ ^{3}}{4} + \frac{11 λ ^{2}}{24} - \frac{6 λ}{24}

Cancel

\frac{6 λ}{24} : \frac{λ}{4}

= \frac{λ ^{4}}{24} - \frac{λ ^{3}}{4} + \frac{11 λ ^{2}}{24} - \frac{λ}{4}

(- 8, - 1) y (- 6, 5) (- 6, 5)

\frac{( 34 x - 442 ) ^{2}}{28561}

\frac{x ^{2} + 2 x - 2}{( x + 1 ) ^{2}}

- \frac{5}{2 ( 2 - 5 x )}

\frac{1}{3} (10 ln (10) - 9)

What is expand (λ(λ-1)(λ-2)(λ-3))/(24) ?
The solution to expand (λ(λ-1)(λ-2)(λ-3))/(24) is (λ^4}{24}-(λ^3)/4+\frac{11λ^2)/(24)-λ/4