What is expand t/((t+3)(t^2+9)) ?

The solution to expand t/((t+3)(t^2+9)) is t/(t^3+9t+3t^2+27)

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expand t/((t+3)(t^2+9))

expand

\frac{t}{( t + 3 ) ( t ^{2} + 9 )}

\frac{t}{t ^{3} + 9 t + 3 t ^{2} + 27}

Solution steps

\frac{t}{( t + 3 ) ( t ^{2} + 9 )}

Expand

(t + 3) (t^{2} + 9) : t^{3} + 9 t + 3 t^{2} + 27

= \frac{t}{t ^{3} + 9 t + 3 t ^{2} + 27}

lo g_{10} (x^{2} + x^{2} - 4 \cdot (x^{2} + 2)^{3})

sec (\frac{3.14}{2})

\frac{10 ( 13 - 2 )}{3}

(x - \frac{3}{2})^{\frac{3}{4}}

\frac{4 ( 3 - x ) ^{4}}{81}

What is expand t/((t+3)(t^2+9)) ?
The solution to expand t/((t+3)(t^2+9)) is t/(t^3+9t+3t^2+27)