What is expand P(1,8,-3)yQ(1,0,8) ?

The solution to expand P(1,8,-3)yQ(1,0,8) is 1*(1*0*8,,)PyQ,8,-3(1*0*8,,)PyQ

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expand P(1,8,-3)yQ(1,0,8)

expand

P (1, 8, - 3) y Q (1, 0, 8)

1 \cdot (1 \cdot 0 \cdot 8,,) P y Q, 8, - 3 (1 \cdot 0 \cdot 8,,) P y Q

Solution steps

P (1, 8, - 3) y Q (1, 0, 8)

= (1 \cdot 8,, - 3) (1 \cdot 0 \cdot 8,,) P y Q

Apply the distributive law:

a (b - c) = ab - a c

a = P y Q (1, 0, 8), b = 1, 8,, c = 3

= P y Q (1, 0, 8) \cdot 1, 8, - P y Q (1, 0, 8) \cdot 3

= 1 \cdot (1 \cdot 0 \cdot 8,,) P y Q, 8, - 3 (1 \cdot 0 \cdot 8,,) P y Q

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What is expand P(1,8,-3)yQ(1,0,8) ?
The solution to expand P(1,8,-3)yQ(1,0,8) is 1*(1*0*8,,)PyQ,8,-3(1*0*8,,)PyQ