What is expand (4(s+2))/(s(s^3+2s^2+3s+4)) ?

The solution to expand (4(s+2))/(s(s^3+2s^2+3s+4)) is (4s+8)/(s^4+2s^3+3s^2+4s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4(s+2))/(s(s^3+2s^2+3s+4))

expand

\frac{4 ( s + 2 )}{s ( s ^{3} + 2 s ^{2} + 3 s + 4 )}

\frac{4 s + 8}{s ^{4} + 2 s ^{3} + 3 s ^{2} + 4 s}

Solution steps

\frac{4 ( s + 2 )}{s ( s ^{3} + 2 s ^{2} + 3 s + 4 )}

Expand

s (s^{3} + 2 s^{2} + 3 s + 4) : s^{4} + 2 s^{3} + 3 s^{2} + 4 s

= \frac{4 ( s + 2 )}{s ^{4} + 2 s ^{3} + 3 s ^{2} + 4 s}

Expand

4 (s + 2) : 4 s + 8

= \frac{4 s + 8}{s ^{4} + 2 s ^{3} + 3 s ^{2} + 4 s}

(\frac{( k s - s ) ( k ^{2} - 1 ) ( s - 1 )}{s ^{2} - s - 2}) + (k - 1)

\frac{x ^{2}}{( 1 + 0.6 x ) ( 1 - x )}

\frac{( 1 + 2 x ) ^{4}}{8}

(- 16 e^{x} sin (x)) (8 e^{x} cos (x) - 8 e^{x} sin (x))

\frac{π ( x ^{6} + 1 )}{3}

What is expand (4(s+2))/(s(s^3+2s^2+3s+4)) ?
The solution to expand (4(s+2))/(s(s^3+2s^2+3s+4)) is (4s+8)/(s^4+2s^3+3s^2+4s)