What is expand (3^{(n+1)*(n+2)}+65)/(72) ?

The solution to expand (3^{(n+1)*(n+2)}+65)/(72) is (3^{n^2+3n})/8+65/72

Popular >

expand (3^{(n+1)*(n+2)}+65)/(72)

expand

\frac{3 ^{(n + 1) \cdot (n + 2)} + 65}{72}

\frac{3 ^{n^{2} + 3 n}}{8} + \frac{65}{72}

Solution steps

\frac{3 ^{(n + 1) (n + 2)} + 65}{72}

Expand

(n + 1) (n + 2) : n^{2} + 3 n + 2

= \frac{3 ^{n^{2} + 3 n + 2} + 65}{72}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 ^{n^{2} + 3 n + 2} + 65}{72} = \frac{3 ^{n^{2} + 3 n + 2}}{72} + \frac{65}{72}

= \frac{3 ^{n^{2} + 3 n + 2}}{72} + \frac{65}{72}

\frac{3 ^{n^{2} + 3 n + 2}}{72} = \frac{3 ^{n^{2} + 3 n}}{8}

= \frac{3 ^{n^{2} + 3 n}}{8} + \frac{65}{72}

\frac{d}{d t} ((s) (\frac{1}{9 π} cos (9 t) - \frac{1}{3 π} sin (3 t)))

\frac{9 x ^{2} + 4}{5 ( 3 x ^{3} + 4 x ) ^{\frac{4}{5}}}

\frac{x ( x + y + z )}{z ( x - y + z )}

(\frac{63}{32})^{2}

\frac{- 4 x ^{2} + 4 x + 4}{( x ^{2} + 1 ) ^{2}}

What is expand (3^{(n+1)*(n+2)}+65)/(72) ?
The solution to expand (3^{(n+1)*(n+2)}+65)/(72) is (3^{n^2+3n})/8+65/72