What is expand 8/((s^2+1)(s^2+9)) ?

The solution to expand 8/((s^2+1)(s^2+9)) is 8/(s^4+10s^2+9)

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expand 8/((s^2+1)(s^2+9))

expand

\frac{8}{( s ^{2} + 1 ) ( s ^{2} + 9 )}

\frac{8}{s ^{4} + 10 s ^{2} + 9}

Solution steps

\frac{8}{( s ^{2} + 1 ) ( s ^{2} + 9 )}

Expand

(s^{2} + 1) (s^{2} + 9) : s^{4} + 10 s^{2} + 9

= \frac{8}{s ^{4} + 10 s ^{2} + 9}

\frac{( 2 y + 1 ) ^{2}}{4}

- 3 (- 27 π^{3} - 1)

\frac{3 e ^{- 2 s}}{s ( s + 1 ) ( s - 3 )}

\frac{2}{x ^{3} ( x + a ) ^{2}}

(2 (y \cdot v) + 4 y) d y

What is expand 8/((s^2+1)(s^2+9)) ?
The solution to expand 8/((s^2+1)(s^2+9)) is 8/(s^4+10s^2+9)