What is expand 320(x/(16)+x/(20)=1) ?

The solution to expand 320(x/(16)+x/(20)=1) is 36x=1

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expand 320(x/(16)+x/(20)=1)

expand

320 (\frac{x}{16} + \frac{x}{20} = 1)

36 x = 1

Solution steps

320 (\frac{x}{16} + \frac{x}{20} = 1)

= 320 (\frac{x}{16} + 1 = \frac{x}{20})

Apply the distributive law:

a (b + c) = ab + a c

a = 320, b = \frac{x}{16}, c = \frac{x}{20} = 1

320 \cdot \frac{x}{16} + 320 \cdot \frac{x}{20} = 1

Expand

320 \cdot \frac{x}{16} + 320 \cdot \frac{x}{20} : 36 x

36 x = 1

\frac{7 x ^{2}}{( x - 4 ) ( x + 7 )}

- 5 (2 + Δ x)

\frac{x - 1}{x ( x + 1 ) ( x + 2 )}

\frac{4 x + 1}{( x + 1 ) ^{3} ( x ^{2} + 6 ) ^{2}}

- \frac{2 x ^{4} + 36 x ^{3} + 243 x ^{2} + 732 x + 838}{( x + 4 ) ^{4}}

What is expand 320(x/(16)+x/(20)=1) ?
The solution to expand 320(x/(16)+x/(20)=1) is 36x=1