What is expand 2(3x+2)(2x+3)-(3x+,1)(4x+3) ?

The solution to expand 2(3x+2)(2x+3)-(3x+,1)(4x+3) is 12x^2+26x+12-3*4xx-3*3x,1*4x,1*3

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expand 2(3x+2)(2x+3)-(3x+,1)(4x+3)

expand

2 (3 x + 2) (2 x + 3) - (3 x +, 1) (4 x + 3)

12 x^{2} + 26 x + 12 - 3 \cdot 4 xx - 3 \cdot 3 x, 1 \cdot 4 x, 1 \cdot 3

Solution steps

2 (3 x + 2) (2 x + 3) - (3 x +, 1) (4 x + 3)

= 2 (3 x + 2) (2 x + 3) - (3 x + 1,) (4 x + 3)

Expand

2 (3 x + 2) (2 x + 3) : 12 x^{2} + 26 x + 12

= 12 x^{2} + 26 x + 12 - (3 x +, 1) (4 x + 3)

Expand

- (3 x +, 1) (4 x + 3) : - 3 \cdot 4 xx - 3 \cdot 3 x, 1 \cdot 4 x, 1 \cdot 3

= 12 x^{2} + 26 x + 12 - 3 \cdot 4 xx - 3 \cdot 3 x, 1 \cdot 4 x, 1 \cdot 3

\frac{sin ^{2} ( x )}{( cos ( x ) + 1 ) ^{2}}

sin (x (π - \frac{π}{k}))

\frac{2 ( - 3 cos ( \frac{πn}{3} ) + 3 )}{π ^{2} n ^{2}}

\frac{\frac{d}{d x} ( ( x + 2 ) ^{2} )}{( x - 4 ) ^{4}}

\frac{( s + 3 )}{s ( s + 1 ) ^{2} ( s + 2 )}

What is expand 2(3x+2)(2x+3)-(3x+,1)(4x+3) ?
The solution to expand 2(3x+2)(2x+3)-(3x+,1)(4x+3) is 12x^2+26x+12-3*4xx-3*3x,1*4x,1*3