What is expand p(-2,3)yq(4,-1) ?

The solution to expand p(-2,3)yq(4,-1) is 4(-2*3,)pyq,-1*(-2*3,)pyq

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expand p(-2,3)yq(4,-1)

expand

p (- 2, 3) y q (4, - 1)

4 (- 2 \cdot 3,) p y q, - 1 \cdot (- 2 \cdot 3,) p y q

Solution steps

p (- 2, 3) y q (4, - 1)

= (- 2 \cdot 3,) (4, - 1) p y q

Apply the distributive law:

a (b - c) = ab - a c

a = p (- 2, 3) y q, b = 4,, c = 1

= p (- 2, 3) y q \cdot 4, - p (- 2, 3) y q \cdot 1

= 4 (- 2 \cdot 3,) p y q, - 1 \cdot (- 2 \cdot 3,) p y q

(2 y^{2} + 9 x) d x + 2 x y d y

π (156 - 72 ln (3))

- \frac{3 ( 1 - 3 5 )}{88}

- \frac{Δ ( Δ + 2 ) x}{( y + Δ y ) ^{2}}

3 sin (\frac{1}{2}) (x + π) + 6

What is expand p(-2,3)yq(4,-1) ?
The solution to expand p(-2,3)yq(4,-1) is 4(-2*3,)pyq,-1*(-2*3,)pyq