What are the solutions to the equation x(x+4)=12 ?

The solutions to the equation x(x+4)=12 are x=2,x=-6

Find the zeros of x(x+4)=12

The zeros of x(x+4)=12 are x=2,x=-6

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x (x + 4) = 12

x = 2, x = - 6

Solution steps

x (x + 4) = 12

Expand

x (x + 4) : x^{2} + 4 x

x^{2} + 4 x = 12

Move

12

to the left side

x^{2} + 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 1}, x_{2} = \frac{- 4 - 8}{2 \cdot 1}

x = \frac{- 4 + 8}{2 \cdot 1} : 2

x = \frac{- 4 - 8}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

20 m^{2} + 13 mn + 2 n^{2}

3 n^{2} - 2 n + 1 = - 3 n^{2} + 9 n + 11

\frac{\frac{25 x ^{2} - y ^{2}}{x y}}{\frac{5}{y} - \frac{1}{x}}

4 + 13 x = 14 x - 4

- x^{2} - 15 > 8 x

What are the solutions to the equation x(x+4)=12 ?
The solutions to the equation x(x+4)=12 are x=2,x=-6
Find the zeros of x(x+4)=12
The zeros of x(x+4)=12 are x=2,x=-6