What is expand (((-1)^n-1))/2 ?

The solution to expand (((-1)^n-1))/2 is ((-1)^n)/2-1/2

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expand (((-1)^n-1))/2

expand

\frac{( ( - 1 ) ^{n} - 1 )}{2}

\frac{( - 1 ) ^{n}}{2} - \frac{1}{2}

Solution steps

\frac{( - 1 ) ^{n} - 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{( - 1 ) ^{n} - 1}{2} = \frac{( - 1 ) ^{n}}{2} - \frac{1}{2}

= \frac{( - 1 ) ^{n}}{2} - \frac{1}{2}

\frac{( x - 2 ) ( x + 1 )}{x ( x + 3 )}

\frac{x + 1 - e ^{- x}}{e ^{- x} ( x + 1 )}

e^{x} (1 - e^{x}) (1 + e^{x})^{10}

2 x e^{x} (x^{2} + e^{x})

\frac{2 ( 8 - 2 a )}{3}

What is expand (((-1)^n-1))/2 ?
The solution to expand (((-1)^n-1))/2 is ((-1)^n)/2-1/2