What is expand (-c(n-2))/(n+1) ?

The solution to expand (-c(n-2))/(n+1) is -(nc-2c)/(n+1)

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expand (-c(n-2))/(n+1)

expand

\frac{- c ( n - 2 )}{n + 1}

- \frac{n c - 2 c}{n + 1}

Solution steps

\frac{- c ( n - 2 )}{n + 1}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{c ( n - 2 )}{n + 1}

Expand

c (n - 2) : n c - 2 c

= - \frac{n c - 2 c}{n + 1}

\frac{e ^{x}}{4 ( 1 - e ^{2 x} )}

(e^{5 x} + 5)^{2}

- \frac{3 ( e ^{π} - 1 )}{73 e ^{3 π}}

(2 x - 4) (3 x - 2) d x

2 e^{x} (e^{x} + 2)

What is expand (-c(n-2))/(n+1) ?
The solution to expand (-c(n-2))/(n+1) is -(nc-2c)/(n+1)