What is expand (x^3-4x^2+2x-5)/((2x-4)^2) ?

The solution to expand (x^3-4x^2+2x-5)/((2x-4)^2) is (x^3-4x^2+2x-5)/(4x^2-16x+16)

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expand (x^3-4x^2+2x-5)/((2x-4)^2)

expand

\frac{x ^{3} - 4 x ^{2} + 2 x - 5}{( 2 x - 4 ) ^{2}}

\frac{x ^{3} - 4 x ^{2} + 2 x - 5}{4 x ^{2} - 16 x + 16}

Solution steps

\frac{x ^{3} - 4 x ^{2} + 2 x - 5}{( 2 x - 4 ) ^{2}}

(2 x - 4)^{2} = 4 x^{2} - 16 x + 16

= \frac{x ^{3} - 4 x ^{2} + 2 x - 5}{4 x ^{2} - 16 x + 16}

- \frac{6 x ^{2} - 8 x + 3}{( x - 1 ) ^{3}}

(x y^{2} - e^{x^{\frac{1}{3}}}) d x - x^{2} y d y

\frac{d}{d t} ((x) (2 - e^{t}))

(27 - 45) (7 + 65)

\frac{( x - 1 ) ^{2}}{x ^{3}}

What is expand (x^3-4x^2+2x-5)/((2x-4)^2) ?
The solution to expand (x^3-4x^2+2x-5)/((2x-4)^2) is (x^3-4x^2+2x-5)/(4x^2-16x+16)