What is expand (2^{1/N})/(N(2^{1/N)-1)} ?

The solution to expand (2^{1/N})/(N(2^{1/N)-1)} is (2^{1/N})/(2^{1/N)N-N}

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expand (2^{1/N})/(N(2^{1/N)-1)}

expand

\frac{2 ^{\frac{1}{N}}}{N ( 2 ^{\frac{1}{N}} - 1 )}

\frac{2 ^{\frac{1}{N}}}{2 ^{\frac{1}{N}} N - N}

Solution steps

\frac{2 ^{\frac{1}{N}}}{N ( 2 ^{\frac{1}{N}} - 1 )}

Expand

N (2^{\frac{1}{N}} - 1) : 2^{\frac{1}{N}} N - N

= \frac{2 ^{\frac{1}{N}}}{2 ^{\frac{1}{N}} N - N}

(\frac{2 - 14}{5})^{2}

\frac{( n ( n - 3 ) )}{2}

\frac{2 x ^{2} + 3 x - 11}{( x - 3 ) ( x + 1 )}

(π - 17)^{2}

\frac{( 0.05 - x ) ( 0.04 - x )}{( 0.086 - x ) ( 0.135 - x )}

What is expand (2^{1/N})/(N(2^{1/N)-1)} ?
The solution to expand (2^{1/N})/(N(2^{1/N)-1)} is (2^{1/N})/(2^{1/N)N-N}