What is expand-((x-y)^3)/3 ?

The solution to expand-((x-y)^3)/3 is -(x^3)/3+x^2y-xy^2+(y^3)/3

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expand-((x-y)^3)/3

expand

- \frac{( x - y ) ^{3}}{3}

- \frac{x ^{3}}{3} + x^{2} y - x y^{2} + \frac{y ^{3}}{3}

Solution steps

- \frac{( x - y ) ^{3}}{3}

(x - y)^{3} = x^{3} - 3 x^{2} y + 3 x y^{2} - y^{3}

= - \frac{x ^{3} - 3 x ^{2} y + 3 x y ^{2} - y ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - 3 x ^{2} y + 3 x y ^{2} - y ^{3}}{3} = - (\frac{x ^{3}}{3}) - (- \frac{3 x ^{2} y}{3}) - (\frac{3 x y ^{2}}{3}) - (- \frac{y ^{3}}{3})

= - (\frac{x ^{3}}{3}) - (- \frac{3 x ^{2} y}{3}) - (\frac{3 x y ^{2}}{3}) - (- \frac{y ^{3}}{3})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{x ^{3}}{3} + \frac{3 x ^{2} y}{3} - \frac{3 x y ^{2}}{3} + \frac{y ^{3}}{3}

Divide the numbers:

\frac{3}{3} = 1

= - \frac{x ^{3}}{3} + x^{2} y - x y^{2} + \frac{y ^{3}}{3}

\frac{1}{x ( x + 4 ) ^{2}}

(x + h) e^{- (x + h)} - x e^{- x}

\frac{3}{s ( s - 2 )}

\frac{e ^{- 2 x}}{( x ^{2} ) ( x - 1 )}

\frac{( 3 x + 1 ) ln ( 3 x + 1 ) + 3 x}{3 x + 1}

What is expand-((x-y)^3)/3 ?
The solution to expand-((x-y)^3)/3 is -(x^3)/3+x^2y-xy^2+(y^3)/3