What is expand ((y+3)(y-6))/((y+1)(2y+3)) ?

The solution to expand ((y+3)(y-6))/((y+1)(2y+3)) is (y^2-3y-18)/(2y^2+5y+3)

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expand ((y+3)(y-6))/((y+1)(2y+3))

expand

\frac{( y + 3 ) ( y - 6 )}{( y + 1 ) ( 2 y + 3 )}

\frac{y ^{2} - 3 y - 18}{2 y ^{2} + 5 y + 3}

Solution steps

\frac{( y + 3 ) ( y - 6 )}{( y + 1 ) ( 2 y + 3 )}

Expand

(y + 1) (2 y + 3) : 2 y^{2} + 5 y + 3

= \frac{( y + 3 ) ( y - 6 )}{2 y ^{2} + 5 y + 3}

Expand

(y + 3) (y - 6) : y^{2} - 3 y - 18

= \frac{y ^{2} - 3 y - 18}{2 y ^{2} + 5 y + 3}

\frac{x ( 3 x + 5 ) + 13}{2 x + 1}

\frac{d}{d y} ((z (y, x)) (e^{x z (y, x)} + x y))

\frac{F}{x ( A x ^{2} + B x + C )}

\frac{3 ( 3 y + x y - 2 x )}{2 x ( y + 5 )}

(x^{3} + 2)^{5} + 2 y^{6} - 6 x^{7} sin (y) + 5 ln (x^{2} + y^{2})

What is expand ((y+3)(y-6))/((y+1)(2y+3)) ?
The solution to expand ((y+3)(y-6))/((y+1)(2y+3)) is (y^2-3y-18)/(2y^2+5y+3)