What is expand (n(3n-1))/2+(3n+1) ?

The solution to expand (n(3n-1))/2+(3n+1) is (3n^2)/2-n/2+3n+1

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expand (n(3n-1))/2+(3n+1)

expand

\frac{n ( 3 n - 1 )}{2} + (3 n + 1)

\frac{3 n ^{2}}{2} - \frac{n}{2} + 3 n + 1

Solution steps

\frac{n ( 3 n - 1 )}{2} + (3 n + 1)

Remove parentheses:

(a) = a

= \frac{n ( 3 n - 1 )}{2} + 3 n + 1

Expand

n (3 n - 1) : 3 n^{2} - n

= \frac{3 n ^{2} - n}{2} + 3 n + 1

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 n ^{2} - n}{2} = \frac{3 n ^{2}}{2} - \frac{n}{2}

= \frac{3 n ^{2}}{2} - \frac{n}{2} + 3 n + 1

a (1, - 1, 0) + b (0, 1, 1) + c (0, 0, 1)

\frac{3 s - 3}{( s - 3 ) ^{2}}

\frac{2}{( x - 3 ) ^{5}}

\frac{e ^{y} ( 1 + x y ) - x e ^{y}}{( 1 + x y ) ^{2}}

(x^{3} - 3 x^{2} + 3 x - 1)^{5}

What is expand (n(3n-1))/2+(3n+1) ?
The solution to expand (n(3n-1))/2+(3n+1) is (3n^2)/2-n/2+3n+1