What is expand 1-e^{-ax}(-2t+1) ?

The solution to expand 1-e^{-ax}(-2t+1) is 1+2e^{-ax}t-e^{-ax}

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expand 1-e^{-ax}(-2t+1)

expand

1 - e^{- a x} (- 2 t + 1)

1 + 2 e^{- a x} t - e^{- a x}

Solution steps

1 - e^{- a x} (- 2 t + 1)

Expand

- e^{- a x} (- 2 t + 1) : 2 e^{- a x} t - e^{- a x}

= 1 + 2 e^{- a x} t - e^{- a x}

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\frac{4 s ^{3} - 2 s ^{2} - 2}{( s + 1 ) ^{2} ( s ^{2} + 1 ) ^{2}}

What is expand 1-e^{-ax}(-2t+1) ?
The solution to expand 1-e^{-ax}(-2t+1) is 1+2e^{-ax}t-e^{-ax}