What is expand (2^x(2^h-1))/h ?

The solution to expand (2^x(2^h-1))/h is (2^{h+x})/h-(2^x)/h

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expand (2^x(2^h-1))/h

expand

\frac{2 ^{x} ( 2 ^{h} - 1 )}{h}

\frac{2 ^{h + x}}{h} - \frac{2 ^{x}}{h}

Solution steps

\frac{2 ^{x} ( 2 ^{h} - 1 )}{h}

Expand

2^{x} (2^{h} - 1) : 2^{h + x} - 2^{x}

= \frac{2 ^{x + h} - 2 ^{x}}{h}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 ^{h + x} - 2 ^{x}}{h} = \frac{2 ^{h + x}}{h} - \frac{2 ^{x}}{h}

= \frac{2 ^{x + h}}{h} - \frac{2 ^{x}}{h}

\frac{( - 2 - x ) ^{2}}{4}

\frac{2 ( 4 - π )}{4}

a (2, - 1, 3)

e^{2 x} (e^{2 x} + x^{2} e^{2 x})

\frac{2 ( 2 e - 1 )}{3 e}

What is expand (2^x(2^h-1))/h ?
The solution to expand (2^x(2^h-1))/h is (2^{h+x})/h-(2^x)/h