What is expand 5(5x^2-2x+1)^2 ?

The solution to expand 5(5x^2-2x+1)^2 is 125x^4-100x^3+70x^2-20x+5

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expand 5(5x^2-2x+1)^2

expand

5 (5 x^{2} - 2 x + 1)^{2}

125 x^{4} - 100 x^{3} + 70 x^{2} - 20 x + 5

Solution steps

5 (5 x^{2} - 2 x + 1)^{2}

(5 x^{2} - 2 x + 1)^{2} = 25 x^{4} - 20 x^{3} + 14 x^{2} - 4 x + 1

= 5 (25 x^{4} - 20 x^{3} + 14 x^{2} - 4 x + 1)

Distribute parentheses

= 5 \cdot 25 x^{4} + 5 (- 20 x^{3}) + 5 \cdot 14 x^{2} + 5 (- 4 x) + 5 \cdot 1

Apply minus-plus rules

+ (- a) = - a

= 5 \cdot 25 x^{4} - 5 \cdot 20 x^{3} + 5 \cdot 14 x^{2} - 5 \cdot 4 x + 5 \cdot 1

Simplify

5 \cdot 25 x^{4} - 5 \cdot 20 x^{3} + 5 \cdot 14 x^{2} - 5 \cdot 4 x + 5 \cdot 1 : 125 x^{4} - 100 x^{3} + 70 x^{2} - 20 x + 5

= 125 x^{4} - 100 x^{3} + 70 x^{2} - 20 x + 5

\frac{( v - 1 ) ( v ^{2} + v + 1 )}{v ^{2}}

(4 y^{2} - 24 y + 34) e^{- y^{2} + 6 y}

\frac{( x + 1 ) ( x - 10 )}{80}

\frac{1 - x ^{2} + x}{( 2 x ^{2} + 3 ) ( x ^{2} + 2 )}

\frac{s ^{2} + 3 s + 4 b}{( s + 2 ) ^{3} ( s + 1 ) ( s + a )}

What is expand 5(5x^2-2x+1)^2 ?
The solution to expand 5(5x^2-2x+1)^2 is 125x^4-100x^3+70x^2-20x+5