What is expand ((-x+6)(-3x-28))/3 ?

The solution to expand ((-x+6)(-3x-28))/3 is x^2+(10x)/3-56

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expand ((-x+6)(-3x-28))/3

expand

\frac{( - x + 6 ) ( - 3 x - 28 )}{3}

x^{2} + \frac{10 x}{3} - 56

Solution steps

\frac{( - x + 6 ) ( - 3 x - 28 )}{3}

Expand

(- x + 6) (- 3 x - 28) : 3 x^{2} + 10 x - 168

= \frac{3 x ^{2} + 10 x - 168}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} + 10 x - 168}{3} = \frac{3 x ^{2}}{3} + \frac{10 x}{3} - \frac{168}{3}

= \frac{3 x ^{2}}{3} + \frac{10 x}{3} - \frac{168}{3}

Divide the numbers:

\frac{3}{3} = 1

= x^{2} + \frac{10 x}{3} - \frac{168}{3}

Divide the numbers:

\frac{168}{3} = 56

= x^{2} + \frac{10 x}{3} - 56

\frac{2 s ^{4} - s ^{3} + 12 s - 12}{s ^{4} ( s - 1 )}

e^{x} \cdot (e^{x} + e^{x} x)

(e^{- 2 x} (2 - x) + x)^{2}

- \frac{54 - 26 x}{x}

\frac{2 ( 2 x - y )}{x}

What is expand ((-x+6)(-3x-28))/3 ?
The solution to expand ((-x+6)(-3x-28))/3 is x^2+(10x)/3-56