What is expand (3x^2+9x-5)/(12) ?

The solution to expand (3x^2+9x-5)/(12) is (x^2)/4+(3x)/4-5/12

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expand (3x^2+9x-5)/(12)

expand

\frac{3 x ^{2} + 9 x - 5}{12}

\frac{x ^{2}}{4} + \frac{3 x}{4} - \frac{5}{12}

Solution steps

\frac{3 x ^{2} + 9 x - 5}{12}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} + 9 x - 5}{12} = \frac{3 x ^{2}}{12} + \frac{9 x}{12} - \frac{5}{12}

= \frac{3 x ^{2}}{12} + \frac{9 x}{12} - \frac{5}{12}

Cancel

\frac{3 x ^{2}}{12} : \frac{x ^{2}}{4}

= \frac{x ^{2}}{4} + \frac{9 x}{12} - \frac{5}{12}

Cancel

\frac{9 x}{12} : \frac{3 x}{4}

= \frac{x ^{2}}{4} + \frac{3 x}{4} - \frac{5}{12}

\frac{( 3 + x ) ^{2} - 3 y ( 2 x - 3 ) - 18 y ^{2}}{2 x ^{2}}

24 e^{- 30 t} + 30 (\frac{4}{5} - \frac{4}{5} e^{- 30 t})

\frac{x ^{3}}{2 ( x + 1 ) ^{2}}

d y (x sin (y) + y cos (x) + g y)

\frac{1 - x + 3 x ^{2}}{( 1 - 4 x + 3 x ^{2} ) ( 1 - x )}

What is expand (3x^2+9x-5)/(12) ?
The solution to expand (3x^2+9x-5)/(12) is (x^2)/4+(3x)/4-5/12