What is expand (3x^2+2x-9)(ln(x^3-5x)) ?

The solution to expand (3x^2+2x-9)(ln(x^3-5x)) is 3x^2ln(x^3-5x)+2xln(x^3-5x)-9ln(x^3-5x)

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expand (3x^2+2x-9)(ln(x^3-5x))

expand

(3 x^{2} + 2 x - 9) (ln (x^{3} - 5 x))

3 x^{2} ln (x^{3} - 5 x) + 2 x ln (x^{3} - 5 x) - 9 ln (x^{3} - 5 x)

Solution steps

(3 x^{2} + 2 x - 9) (ln (x^{3} - 5 x))

= (ln (x^{3} - 5 x)) (3 x^{2} + 2 x - 9)

Distribute parentheses

= (ln (x^{3} - 5 x)) \cdot 3 x^{2} + (ln (x^{3} - 5 x)) \cdot 2 x + (ln (x^{3} - 5 x)) (- 9)

Apply minus-plus rules

+ (- a) = - a

= 3 x^{2} (ln (x^{3} - 5 x)) + 2 x (ln (x^{3} - 5 x)) - 9 (ln (x^{3} - 5 x))

Remove parentheses:

(a) = a

= 3 x^{2} ln (x^{3} - 5 x) + 2 x ln (x^{3} - 5 x) - 9 ln (x^{3} - 5 x)

\frac{d}{d t} ((x) (a (t + sin (t) cos (t))))

lo g_{a} (b) lo g_{b} (c) lo g_{c} (a)

1 + \frac{0.024 X}{( s + 0.2 ) ( s + 0.1 )}

a r gu m e n t (1 + i)

\frac{( s + 1 ) ^{2}}{( s + 4 ) ^{4}}

What is expand (3x^2+2x-9)(ln(x^3-5x)) ?
The solution to expand (3x^2+2x-9)(ln(x^3-5x)) is 3x^2ln(x^3-5x)+2xln(x^3-5x)-9ln(x^3-5x)