What is expand ((12-x-y)^2)/4 ?

The solution to expand ((12-x-y)^2)/4 is (xy)/2-6x+(x^2)/4-6y+(y^2)/4+36

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expand ((12-x-y)^2)/4

expand

\frac{( 12 - x - y ) ^{2}}{4}

\frac{x y}{2} - 6 x + \frac{x ^{2}}{4} - 6 y + \frac{y ^{2}}{4} + 36

Solution steps

\frac{( 12 - x - y ) ^{2}}{4}

(12 - x - y)^{2} = 2 x y - 24 x + x^{2} - 24 y + y^{2} + 144

= \frac{2 x y - 24 x + x ^{2} - 24 y + y ^{2} + 144}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x y - 24 x + x ^{2} - 24 y + y ^{2} + 144}{4} = \frac{2 x y}{4} - \frac{24 x}{4} + \frac{x ^{2}}{4} - \frac{24 y}{4} + \frac{y ^{2}}{4} + \frac{144}{4}

= \frac{2 x y}{4} - \frac{24 x}{4} + \frac{x ^{2}}{4} - \frac{24 y}{4} + \frac{y ^{2}}{4} + \frac{144}{4}

\frac{2 x y}{4} = \frac{x y}{2}

\frac{24 x}{4} = 6 x

\frac{24 y}{4} = 6 y

\frac{144}{4} = 36

= \frac{x y}{2} - 6 x + \frac{x ^{2}}{4} - 6 y + \frac{y ^{2}}{4} + 36

\frac{13 ( 3 x ^{2} - 2 3 x y + y ^{2} )}{4}

p ro d u c t (3 x + 2) (4 x^{2} - 7 x + 1) i s

\frac{1}{t ( t - 11 )}

(\frac{- x + 10}{3})^{2}

\frac{7 s}{( s ^{2} + k ^{2} ) ( s - 1 )}

What is expand ((12-x-y)^2)/4 ?
The solution to expand ((12-x-y)^2)/4 is (xy)/2-6x+(x^2)/4-6y+(y^2)/4+36