What is (\partial)/(\partial t)((y)(pi-t)) ?

The answer to (\partial)/(\partial t)((y)(pi-t)) is -y

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(\partial)/(\partial t)((y)(pi-t))

\frac{\partial}{\partial t} ((y) (π - t))

- y

Solution steps

\frac{\partial}{\partial t} ((y) (π - t))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial t} (π - t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= y (\frac{\partial}{\partial t} (π) - \frac{\partial}{\partial t} (t))

\frac{\partial}{\partial t} (π) = 0

\frac{\partial}{\partial t} (t) = 1

= y (0 - 1)

Simplify

= - y

59 - 3 (3 x + 5 = 28)

x y^{'} (x) + 3 (y + x^{2})

- a (- a + 2) + 1

\frac{1 - e ^{- 2 x}}{x ( x + 2 ) ( x - 1 )}

\frac{- 2 x ^{2} + 4}{x ( x ^{2} + 4 ) ( x ^{2} + 1 )}

What is (\partial)/(\partial t)((y)(pi-t)) ?
The answer to (\partial)/(\partial t)((y)(pi-t)) is -y