What is expand (3(2-z)^2)/2 ?

The solution to expand (3(2-z)^2)/2 is (3z^2)/2-6z+6

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expand (3(2-z)^2)/2

expand

\frac{3 ( 2 - z ) ^{2}}{2}

\frac{3 z ^{2}}{2} - 6 z + 6

Solution steps

\frac{3 ( 2 - z ) ^{2}}{2}

(2 - z)^{2} = 4 - 4 z + z^{2}

= \frac{3 ( z ^{2} - 4 z + 4 )}{2}

Expand

3 (4 - 4 z + z^{2}) : 12 - 12 z + 3 z^{2}

= \frac{12 - 12 z + 3 z ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{12 - 12 z + 3 z ^{2}}{2} = \frac{12}{2} - \frac{12 z}{2} + \frac{3 z ^{2}}{2}

= \frac{12}{2} - \frac{12 z}{2} + \frac{3 z ^{2}}{2}

Divide the numbers:

\frac{12}{2} = 6

= 6 - 6 z + \frac{3 z ^{2}}{2}

Rewrite in standard form

= \frac{3 z ^{2}}{2} - 6 z + 6

(- 1, 2) y (4, - 2)

(1 + sin^{2} (x)) d x

4 x^{2} + 16 x + 16 \cdot 2 x + 4

- \frac{6 ( x + 1 ) ( x - 3 )}{3 - 2 x}

\frac{( y + 1 ) ^{2}}{9}

What is expand (3(2-z)^2)/2 ?
The solution to expand (3(2-z)^2)/2 is (3z^2)/2-6z+6