What is expand (e^x(x-3))/(x^4) ?

The solution to expand (e^x(x-3))/(x^4) is (e^x)/(x^3)-(3e^x)/(x^4)

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expand (e^x(x-3))/(x^4)

expand

\frac{e ^{x} ( x - 3 )}{x ^{4}}

\frac{e ^{x}}{x ^{3}} - \frac{3 e ^{x}}{x ^{4}}

Solution steps

\frac{e ^{x} ( x - 3 )}{x ^{4}}

Expand

e^{x} (x - 3) : e^{x} x - 3 e^{x}

= \frac{e ^{x} x - 3 e ^{x}}{x ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{x} x - 3 e ^{x}}{x ^{4}} = \frac{e ^{x} x}{x ^{4}} - \frac{3 e ^{x}}{x ^{4}}

= \frac{e ^{x} x}{x ^{4}} - \frac{3 e ^{x}}{x ^{4}}

Cancel

\frac{e ^{x} x}{x ^{4}} : \frac{e ^{x}}{x ^{3}}

= \frac{e ^{x}}{x ^{3}} - \frac{3 e ^{x}}{x ^{4}}

(4 E (x, y) x - 5 E (x, y) y = 14.17) x - 2

\frac{2 x + 2 sin ( 2 x ) ( x ^{2} + 1 )}{cos ( 2 x )}

\frac{( x ^{2} - 3 x - 4 b - 12 )}{x ( x + b )}

s ((s + 0.5) (s + 1) (s^{2} + 0.4 s + 4))

(e + f + e^{4} + f^{4}) (e + f - e^{4} + f^{4})

What is expand (e^x(x-3))/(x^4) ?
The solution to expand (e^x(x-3))/(x^4) is (e^x)/(x^3)-(3e^x)/(x^4)