What is expand (4x^2-9)/((x-1)x) ?

The solution to expand (4x^2-9)/((x-1)x) is (4x^2-9)/(x^2-x)

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expand (4x^2-9)/((x-1)x)

expand

\frac{4 x ^{2} - 9}{( x - 1 ) x}

\frac{4 x ^{2} - 9}{x ^{2} - x}

Solution steps

\frac{4 x ^{2} - 9}{( x - 1 ) x}

Expand

(x - 1) x : x^{2} - x

= \frac{4 x ^{2} - 9}{x ^{2} - x}

(\frac{y ^{2}}{2} + ln ∣ y ∣ + C) (3 x^{2} + C)

\frac{s + 2}{( s + 1 ) ^{2} s}

\frac{1}{( 1 + e ^{x} ) ^{2}}

\frac{( e ^{2 π} - 1 ) ( - 1 ) ^{n}}{π e ^{π} ( n ^{2} + 1 )}

- \frac{1}{12 ( 4 x + 3 ) ^{3}}

What is expand (4x^2-9)/((x-1)x) ?
The solution to expand (4x^2-9)/((x-1)x) is (4x^2-9)/(x^2-x)