What is expand (-e^{2x}+2xe^{2x})/(2(2x+1)) ?

The solution to expand (-e^{2x}+2xe^{2x})/(2(2x+1)) is (-e^{2x}+2e^{2x}x)/(4x+2)

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expand (-e^{2x}+2xe^{2x})/(2(2x+1))

expand

\frac{- e ^{2 x} + 2 x e ^{2 x}}{2 ( 2 x + 1 )}

\frac{- e ^{2 x} + 2 e ^{2 x} x}{4 x + 2}

Solution steps

\frac{- e ^{2 x} + 2 x e ^{2 x}}{2 ( 2 x + 1 )}

Expand

2 (2 x + 1) : 4 x + 2

= \frac{- e ^{2 x} + 2 e ^{2 x} x}{4 x + 2}

5 x (- 8 + 10) + x (- 410 + 5)

(e^{- t} - 4 e^{\frac{1}{2}}) (\frac{1}{8} - \frac{1}{8} e^{- 2 t})

\frac{s + 1}{s ( s + 0.1 ) ( s + 10 ) ( s + 100 )}

\frac{( 3 + 2 x ) ^{3}}{6}

\frac{24}{( s + 1 ) ( s ^{2} + 6 s + 13 )}

What is expand (-e^{2x}+2xe^{2x})/(2(2x+1)) ?
The solution to expand (-e^{2x}+2xe^{2x})/(2(2x+1)) is (-e^{2x}+2e^{2x}x)/(4x+2)