What is expand (2(3e^{3pi}+1)(3e^{3pi}-1))/(e^{6pi)} ?

The solution to expand (2(3e^{3pi}+1)(3e^{3pi}-1))/(e^{6pi)} is 18-2/(e^{6pi)}

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expand (2(3e^{3pi}+1)(3e^{3pi}-1))/(e^{6pi)}

expand

\frac{2 ( 3 e ^{3 π} + 1 ) ( 3 e ^{3 π} - 1 )}{e ^{6 π}}

18 - \frac{2}{e ^{6 π}}

Decimal Notation

17.99999 \dots

Solution steps

\frac{2 ( 3 e ^{3 π} + 1 ) ( 3 e ^{3 π} - 1 )}{e ^{6 π}}

Expand

2 (3 e^{3 π} + 1) (3 e^{3 π} - 1) : 18 e^{6 π} - 2

= \frac{18 e ^{6 π} - 2}{e ^{6 π}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{18 e ^{6 π} - 2}{e ^{6 π}} = \frac{18 e ^{6 π}}{e ^{6 π}} - \frac{2}{e ^{6 π}}

= \frac{18 e ^{6 π}}{e ^{6 π}} - \frac{2}{e ^{6 π}}

Cancel

\frac{18 e ^{6 π}}{e ^{6 π}} : 18

= 18 - \frac{2}{e ^{6 π}}

\frac{4 x ^{3}}{( x + 1 ) ^{2} ( x ^{2} - 1 )}

1576 x ((2, \frac{5}{2}) - 1)

\frac{2 ( x - y ) ^{2} ( 3 x + y ) ^{2} ( 1 + x )}{( 1 - x ) ^{4} ( 1 - x + y )}

[(x - 2) e x] \frac{d x}{d x}

[(x - 3) e x]

What is expand (2(3e^{3pi}+1)(3e^{3pi}-1))/(e^{6pi)} ?
The solution to expand (2(3e^{3pi}+1)(3e^{3pi}-1))/(e^{6pi)} is 18-2/(e^{6pi)}