What is expand ((sin(x)+xcos(x))y)/(xsin(x)) ?

The solution to expand ((sin(x)+xcos(x))y)/(xsin(x)) is y/x+(ycos(x))/(sin(x))

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expand ((sin(x)+xcos(x))y)/(xsin(x))

expand

\frac{( sin ( x ) + x cos ( x ) ) y}{x sin ( x )}

\frac{y}{x} + \frac{y cos ( x )}{sin ( x )}

Solution steps

\frac{( sin ( x ) + x cos ( x ) ) y}{x sin ( x )}

Expand

(sin (x) + x cos (x)) y : y sin (x) + x y cos (x)

= \frac{y sin ( x ) + x y cos ( x )}{x sin ( x )}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{y sin ( x ) + x y cos ( x )}{x sin ( x )} = \frac{y sin ( x )}{x sin ( x )} + \frac{x y cos ( x )}{x sin ( x )}

= \frac{y sin ( x )}{x sin ( x )} + \frac{x y cos ( x )}{x sin ( x )}

Cancel

\frac{y sin ( x )}{x sin ( x )} : \frac{y}{x}

= \frac{y}{x} + \frac{x y cos ( x )}{x sin ( x )}

Cancel

\frac{x y cos ( x )}{x sin ( x )} : \frac{y cos ( x )}{sin ( x )}

= \frac{y}{x} + \frac{y cos ( x )}{sin ( x )}

\frac{( x + 5 ) ( x - 2 )}{2}

\frac{2}{( s + 2 ) ^{3}}

(1 + i 1 - i - 1 + i, - 1 - i) \cdot (3 - 4 i 6 - 2 i 1 + 2 i 4 + 3 i)

\frac{( 10 x ^{2} - x + 3 ) ( x - 5 )}{2 x ^{2}}

A (- 1, 3) B (2, - 1)

What is expand ((sin(x)+xcos(x))y)/(xsin(x)) ?
The solution to expand ((sin(x)+xcos(x))y)/(xsin(x)) is y/x+(ycos(x))/(sin(x))