What is expand ((6x+1)(9x-2))/2 ?

The solution to expand ((6x+1)(9x-2))/2 is 27x^2-(3x)/2-1

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expand ((6x+1)(9x-2))/2

expand

\frac{( 6 x + 1 ) ( 9 x - 2 )}{2}

27 x^{2} - \frac{3 x}{2} - 1

Solution steps

\frac{( 6 x + 1 ) ( 9 x - 2 )}{2}

Expand

(6 x + 1) (9 x - 2) : 54 x^{2} - 3 x - 2

= \frac{54 x ^{2} - 3 x - 2}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{54 x ^{2} - 3 x - 2}{2} = \frac{54 x ^{2}}{2} - \frac{3 x}{2} - \frac{2}{2}

= \frac{54 x ^{2}}{2} - \frac{3 x}{2} - \frac{2}{2}

Apply rule

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{54 x ^{2}}{2} - \frac{3 x}{2} - 1

Divide the numbers:

\frac{54}{2} = 27

= 27 x^{2} - \frac{3 x}{2} - 1

2 sin (x) (- sin (x) cos (x))

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\frac{3 ( c - x ^{3} ) ^{2} + 3 c + 6 x ^{3}}{( c - x ^{3} ) ^{2}}

\frac{1}{2 x ^{2} ( x + 1 )}

\frac{a ^{2}}{s ( a + s ) ^{2}}

What is expand ((6x+1)(9x-2))/2 ?
The solution to expand ((6x+1)(9x-2))/2 is 27x^2-(3x)/2-1