What are the solutions to the equation u^2-9u+18=0 ?

The solutions to the equation u^2-9u+18=0 are u=6,u=3

Find the zeros of u^2-9u+18=0

The zeros of u^2-9u+18=0 are u=6,u=3

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u^{2} - 9 u + 18 = 0

u = 6, u = 3

Solution steps

u^{2} - 9 u + 18 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

u_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, u_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

u = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

u = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

u = 6, u = 3

1 0^{\frac{1}{2}} \cdot 1 0^{\frac{1}{2}}

s + 130 = - 45

15 x + (- 6 x + 5) - 2 - (- x + 3) = - (7 x + 23) - x + (3 - 2 x)

k^{2} - 2 k

n^{2} - 8 n - 65

What are the solutions to the equation u^2-9u+18=0 ?
The solutions to the equation u^2-9u+18=0 are u=6,u=3
Find the zeros of u^2-9u+18=0
The zeros of u^2-9u+18=0 are u=6,u=3