What is expand f(35(t-4/5))\H(t-4/5) ?

The solution to expand f(35(t-4/5))\H(t-4/5) is 35ft\H(t-4/5)-28f\H(t-4/5)

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expand f(35(t-4/5))\H(t-4/5)

expand

f (35 (t - \frac{4}{5})) H (t - \frac{4}{5})

35 f t H (t - \frac{4}{5}) - 28 f H (t - \frac{4}{5})

Solution steps

f (35 (t - \frac{4}{5})) H (t - \frac{4}{5})

Remove parentheses:

(a) = a

= f \cdot 35 (t - \frac{4}{5}) H (t - \frac{4}{5})

= 35 f H (t - \frac{4}{5}) (t - \frac{4}{5})

Apply the distributive law:

a (b - c) = ab - a c

a = f \cdot 35 H (t - \frac{4}{5}), b = t, c = \frac{4}{5}

= f \cdot 35 H (t - \frac{4}{5}) t - f \cdot 35 H (t - \frac{4}{5}) \frac{4}{5}

= 35 f t H (t - \frac{4}{5}) - 35 \cdot \frac{4}{5} f H (t - \frac{4}{5})

35 \cdot \frac{4}{5} f H (t - \frac{4}{5}) = 28 f H (t - \frac{4}{5})

= 35 f t H (t - \frac{4}{5}) - 28 f H (t - \frac{4}{5})

- \frac{( h - 8 ) ( h - 12 )}{4}

\frac{1}{( x ^{2} + 1 ) ( s ^{2} + x ^{2} )}

f (t - 6) H (t - 6)

1 + x^{2} (9 x^{2} + 6)

(e^{4 x} + 4)^{2}

What is expand f(35(t-4/5))\H(t-4/5) ?
The solution to expand f(35(t-4/5))\H(t-4/5) is 35ft\H(t-4/5)-28f\H(t-4/5)