What is expand 1/((x^2-A)(x^2-B)) ?

The solution to expand 1/((x^2-A)(x^2-B)) is 1/(x^4-Bx^2-Ax^2+AB)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/((x^2-A)(x^2-B))

expand

\frac{1}{( x ^{2} - A ) ( x ^{2} - B )}

\frac{1}{x ^{4} - B x ^{2} - A x ^{2} + A B}

Solution steps

\frac{1}{( x ^{2} - A ) ( x ^{2} - B )}

Expand

(x^{2} - A) (x^{2} - B) : x^{4} - B x^{2} - A x^{2} + A B

= \frac{1}{x ^{4} - B x ^{2} - A x ^{2} + A B}

(x + 2) ln (x + 2)

\frac{x ^{2} ( x - 3 )}{x + 4}

(x + 2 y) d x

\frac{5 ( 12242 - 72 )}{2}

18 0^{\circ} (n - 2)

What is expand 1/((x^2-A)(x^2-B)) ?
The solution to expand 1/((x^2-A)(x^2-B)) is 1/(x^4-Bx^2-Ax^2+AB)