What is expand 2-3((x+1)/(n+2)) ?

The solution to expand 2-3((x+1)/(n+2)) is 2-(3x+3)/(n+2)

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expand 2-3((x+1)/(n+2))

expand

2 - 3 (\frac{x + 1}{n + 2})

2 - \frac{3 x + 3}{n + 2}

Solution steps

2 - 3 (\frac{x + 1}{n + 2})

Remove parentheses:

(a) = a

= 2 - 3 \cdot \frac{x + 1}{n + 2}

3 \cdot \frac{x + 1}{n + 2} = \frac{3 x + 3}{n + 2}

= 2 - \frac{3 x + 3}{n + 2}

(x + h)^{2} - 4 - x^{2} - 4

\frac{40 ( x ^{2} + 10 x + 100 )}{x ( x + 1 ) ( x + 100 )}

ln (x) (x + x^{2})

\frac{x ^{2} y ( y ^{2} - 1 ) ( x ^{2} + 3 y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

\frac{15 π ( - 17 + 5 )}{4}

What is expand 2-3((x+1)/(n+2)) ?
The solution to expand 2-3((x+1)/(n+2)) is 2-(3x+3)/(n+2)