What is expand (10x^2+7x-42)/((x-2)(x+4)(x-1)) ?

The solution to expand (10x^2+7x-42)/((x-2)(x+4)(x-1)) is (10x^2+7x-42)/(x^3+x^2-10x+8)

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expand (10x^2+7x-42)/((x-2)(x+4)(x-1))

expand

\frac{10 x ^{2} + 7 x - 42}{( x - 2 ) ( x + 4 ) ( x - 1 )}

\frac{10 x ^{2} + 7 x - 42}{x ^{3} + x ^{2} - 10 x + 8}

Solution steps

\frac{10 x ^{2} + 7 x - 42}{( x - 2 ) ( x + 4 ) ( x - 1 )}

Expand

(x - 2) (x + 4) (x - 1) : x^{3} + x^{2} - 10 x + 8

= \frac{10 x ^{2} + 7 x - 42}{x ^{3} + x ^{2} - 10 x + 8}

\frac{d}{d x} ((z) (sin (y z) - x - 2 y - 3 z))

t^{2} e^{t} u (t - 1)

lo g_{10} (7) (a^{2} b^{3} c)

\frac{x ^{3}}{x ^{10}}

cos (θ) (tan (θ) + cot (θ) = csc (θ))

What is expand (10x^2+7x-42)/((x-2)(x+4)(x-1)) ?
The solution to expand (10x^2+7x-42)/((x-2)(x+4)(x-1)) is (10x^2+7x-42)/(x^3+x^2-10x+8)