What is expand (x+8)/((x-2)(x+1)(x+2)) ?

The solution to expand (x+8)/((x-2)(x+1)(x+2)) is (x+8)/(x^3+x^2-4x-4)

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expand (x+8)/((x-2)(x+1)(x+2))

expand

\frac{x + 8}{( x - 2 ) ( x + 1 ) ( x + 2 )}

\frac{x + 8}{x ^{3} + x ^{2} - 4 x - 4}

Solution steps

\frac{x + 8}{( x - 2 ) ( x + 1 ) ( x + 2 )}

Expand

(x - 2) (x + 1) (x + 2) : x^{3} + x^{2} - 4 x - 4

= \frac{x + 8}{x ^{3} + x ^{2} - 4 x - 4}

\frac{x ^{2} + 6 x + 8}{( x + 3 ) ^{2}}

\frac{1}{a _{1} ( a _{1} + d )}

- \frac{( s - 4 )}{( s + 1 ) ( s ^{2} + 4 )}

x (1 + y^{2})^{\frac{1}{2}} d x - y (1 + x^{2}) d x

What is expand (x+8)/((x-2)(x+1)(x+2)) ?
The solution to expand (x+8)/((x-2)(x+1)(x+2)) is (x+8)/(x^3+x^2-4x-4)