What is expand-(3(s^2-3s+4))/((s-2)(s^2-4s+5)) ?

The solution to expand-(3(s^2-3s+4))/((s-2)(s^2-4s+5)) is -(3s^2-9s+12)/(s^3-6s^2+13s-10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(3(s^2-3s+4))/((s-2)(s^2-4s+5))

expand

- \frac{3 ( s ^{2} - 3 s + 4 )}{( s - 2 ) ( s ^{2} - 4 s + 5 )}

- \frac{3 s ^{2} - 9 s + 12}{s ^{3} - 6 s ^{2} + 13 s - 10}

Solution steps

- \frac{3 ( s ^{2} - 3 s + 4 )}{( s - 2 ) ( s ^{2} - 4 s + 5 )}

Expand

(s - 2) (s^{2} - 4 s + 5) : s^{3} - 6 s^{2} + 13 s - 10

= - \frac{3 ( s ^{2} - 3 s + 4 )}{s ^{3} - 6 s ^{2} + 13 s - 10}

Expand

3 (s^{2} - 3 s + 4) : 3 s^{2} - 9 s + 12

= - \frac{3 s ^{2} - 9 s + 12}{s ^{3} - 6 s ^{2} + 13 s - 10}

\frac{( t ^{2} + 8 )}{( t - 3 ) ( t - 2 )}

d (y^{'} (d) + \frac{9 y ( d ) ( d ) ^{2}}{2})

\frac{( x ^{2} + y ^{2} - 1 ) ^{3}}{x ^{2} y ^{3}}

(x - 1) + (3 x + 3)

\frac{1}{2 x ,} (x - 1) + x,

What is expand-(3(s^2-3s+4))/((s-2)(s^2-4s+5)) ?
The solution to expand-(3(s^2-3s+4))/((s-2)(s^2-4s+5)) is -(3s^2-9s+12)/(s^3-6s^2+13s-10)