What is expand (2n+1)sin(pi/(3^n)) ?

The solution to expand (2n+1)sin(pi/(3^n)) is 2nsin(pi/(3^n))+sin(pi/(3^n))

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expand (2n+1)sin(pi/(3^n))

expand

(2 n + 1) sin (\frac{π}{3 ^{n}})

2 n sin (\frac{π}{3 ^{n}}) + sin (\frac{π}{3 ^{n}})

Solution steps

(2 n + 1) sin (\frac{π}{3 ^{n}})

= sin (\frac{π}{3 ^{n}}) (2 n + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = sin (\frac{π}{3 ^{n}}), b = 2 n, c = 1

= sin (\frac{π}{3 ^{n}}) \cdot 2 n + sin (\frac{π}{3 ^{n}}) \cdot 1

= 2 n sin (\frac{π}{3 ^{n}}) + 1 \cdot sin (\frac{π}{3 ^{n}})

Multiply:

1 \cdot sin (\frac{π}{3 ^{n}}) = sin (\frac{π}{3 ^{n}})

= 2 n sin (\frac{π}{3 ^{n}}) + sin (\frac{π}{3 ^{n}})

e^{3 x} Q + 3 e^{3 x} (P + Q x)

3 (x^{2} + y^{2}) d x + 7 x y d y

\frac{8 e ^{- π x}}{( x ^{2} + 1 ) ( x ^{2} + 9 )}

\frac{2 x ^{2} - 14 x + 21}{( x - 3 ) ^{2}}

\frac{2 z ( z + 4 )}{z - 1}

What is expand (2n+1)sin(pi/(3^n)) ?
The solution to expand (2n+1)sin(pi/(3^n)) is 2nsin(pi/(3^n))+sin(pi/(3^n))