What is expand (e^{-s}-2e^{-2s})/(s(s^2-3s+2)) ?

The solution to expand (e^{-s}-2e^{-2s})/(s(s^2-3s+2)) is (e^{-s}-2e^{-2s})/(s^3-3s^2+2s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (e^{-s}-2e^{-2s})/(s(s^2-3s+2))

expand

\frac{e ^{- s} - 2 e ^{- 2 s}}{s ( s ^{2} - 3 s + 2 )}

\frac{e ^{- s} - 2 e ^{- 2 s}}{s ^{3} - 3 s ^{2} + 2 s}

Solution steps

\frac{e ^{- s} - 2 e ^{- 2 s}}{s ( s ^{2} - 3 s + 2 )}

Expand

s (s^{2} - 3 s + 2) : s^{3} - 3 s^{2} + 2 s

= \frac{e ^{- s} - 2 e ^{- 2 s}}{s ^{3} - 3 s ^{2} + 2 s}

2 (ln (2 x) + b) + 3 e^{b} x

1 + (a + b)^{2}

\frac{10}{( s + 2 ) ( s + 5 )}

(2 x y^{2} + y e^{x}) d x + (2 x^{2} y + e^{x} - 1) d y

cos (4 (π + θ))

What is expand (e^{-s}-2e^{-2s})/(s(s^2-3s+2)) ?
The solution to expand (e^{-s}-2e^{-2s})/(s(s^2-3s+2)) is (e^{-s}-2e^{-2s})/(s^3-3s^2+2s)