What is expand ln(x)(2x^2+x)-x^2-x ?

The solution to expand ln(x)(2x^2+x)-x^2-x is 2x^2ln(x)+xln(x)-x^2-x

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expand ln(x)(2x^2+x)-x^2-x

expand

ln (x) (2 x^{2} + x) - x^{2} - x

2 x^{2} ln (x) + x ln (x) - x^{2} - x

Solution steps

ln (x) (2 x^{2} + x) - x^{2} - x

Expand

ln (x) (2 x^{2} + x) : 2 x^{2} ln (x) + x ln (x)

= 2 x^{2} ln (x) + x ln (x) - x^{2} - x

3 (t + 1 = 18)

- (\frac{( 6 t + 55 )}{( ( t - 5 ) ( t + 5 ) )})

\frac{2}{( x + 1 ) ^{2} \cdot ( x ^{2} + 1 )}

\frac{5}{x ( x ^{2} + 2 x + 5 )}

H (t - 4) (2 - t^{2}) + 3 e^{- π t} + sin (5 t - t^{3})

What is expand ln(x)(2x^2+x)-x^2-x ?
The solution to expand ln(x)(2x^2+x)-x^2-x is 2x^2ln(x)+xln(x)-x^2-x