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Popular >

d/(d{x)}(({z}(x,y))({x}^3{y}-{y}^{{y}}))

Solution

\frac{d}{d x} ((z (x, y)) (x^{3} y - y^{y}))

Solution

z (x, y) (3 x^{2} y - 0)

Solution steps

\frac{d}{d x} ((z (x, y)) (x^{3} y - y^{y}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z (x, y) \frac{d}{d x} (x^{3} y - y^{y})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (x, y) (\frac{d}{d x} (x^{3} y) - \frac{d}{d x} (y^{y}))

\frac{d}{d x} (x^{3} y) = 3 x^{2} y

\frac{d}{d x} (y^{y}) = 0

= z (x, y) (3 x^{2} y - 0)

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Frequently Asked Questions (FAQ)

What is the d/(d{x)}(({z}(x,y))({x}^3{y}-{y}^{{y}})) ?
The d/(d{x)}(({z}(x,y))({x}^3{y}-{y}^{{y}})) is {z}(x,y)(3{x}^2{y}-0)
What is the first d/(d{x)}(({z}(x,y))({x}^3{y}-{y}^{{y}})) ?
The first d/(d{x)}(({z}(x,y))({x}^3{y}-{y}^{{y}})) is {z}(x,y)(3{x}^2{y}-0)