What is expand (e^{-4x})/((x+3)(x-9)) ?

The solution to expand (e^{-4x})/((x+3)(x-9)) is (e^{-4x})/(x^2-6x-27)

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expand (e^{-4x})/((x+3)(x-9))

expand

\frac{e ^{- 4 x}}{( x + 3 ) ( x - 9 )}

\frac{e ^{- 4 x}}{x ^{2} - 6 x - 27}

Solution steps

\frac{e ^{- 4 x}}{( x + 3 ) ( x - 9 )}

Expand

(x + 3) (x - 9) : x^{2} - 6 x - 27

= \frac{e ^{- 4 x}}{x ^{2} - 6 x - 27}

(x^{2} - x + 4)^{8}

\frac{( x - 1 ) ( x + 1 )}{( x + 5 ) ( x - 5 )}

(- e^{x} x - e^{x}) (x + e^{x})

(3 x e^{y} + 2 y) d x + (x^{2} e^{y} + x) d y

\frac{( x - 2 ) ( 3 x + 1 )}{3}

What is expand (e^{-4x})/((x+3)(x-9)) ?
The solution to expand (e^{-4x})/((x+3)(x-9)) is (e^{-4x})/(x^2-6x-27)