What is expand ((x-2)(x+3))/((x-1)(x+2)) ?

The solution to expand ((x-2)(x+3))/((x-1)(x+2)) is (x^2+x-6)/(x^2+x-2)

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expand ((x-2)(x+3))/((x-1)(x+2))

expand

\frac{( x - 2 ) ( x + 3 )}{( x - 1 ) ( x + 2 )}

\frac{x ^{2} + x - 6}{x ^{2} + x - 2}

Solution steps

\frac{( x - 2 ) ( x + 3 )}{( x - 1 ) ( x + 2 )}

Expand

(x - 1) (x + 2) : x^{2} + x - 2

= \frac{( x - 2 ) ( x + 3 )}{x ^{2} + x - 2}

Expand

(x - 2) (x + 3) : x^{2} + x - 6

= \frac{x ^{2} + x - 6}{x ^{2} + x - 2}

(e^{2} + 1) u^{2}

\frac{\partial}{\partial r} ((x) (r + s))

\frac{5 x + 2}{( x + 2 ) ( x + 1 )}

x (x y^{2} + x^{2} = x + 3 y)

\frac{2 y ^{2} - 2 x ^{2}}{( x ^{2} + y ^{2} ) ^{2}}

What is expand ((x-2)(x+3))/((x-1)(x+2)) ?
The solution to expand ((x-2)(x+3))/((x-1)(x+2)) is (x^2+x-6)/(x^2+x-2)