What is expand (-(W)(L+x)^2)/2+(2LWx) ?

The solution to expand (-(W)(L+x)^2)/2+(2LWx) is -(WL^2)/2+WLx-(Wx^2)/2

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expand (-(W)(L+x)^2)/2+(2LWx)

expand

\frac{- ( W ) ( L + x ) ^{2}}{2} + (2 L W x)

- \frac{W L ^{2}}{2} + W Lx - \frac{W x ^{2}}{2}

Solution steps

\frac{- ( W ) ( L + x ) ^{2}}{2} + (2 L W x)

Remove parentheses:

(a) = a

= \frac{- W ( L + x ) ^{2}}{2} + 2 L W x

\frac{- W ( L + x ) ^{2}}{2} = - \frac{W L ^{2} + 2 W Lx + W x ^{2}}{2}

= - \frac{W L ^{2} + 2 W Lx + W x ^{2}}{2} + 2 W Lx

Convert element to fraction:

2 W Lx = \frac{2 L W x 2}{2}

= - \frac{W L ^{2} + 2 W Lx + W x ^{2}}{2} + \frac{2 L W x \cdot 2}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- ( W L ^{2} + 2 W Lx + W x ^{2} ) + 2 L W x \cdot 2}{2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{- ( W L ^{2} + 2 W Lx + W x ^{2} ) + 4 W Lx}{2}

Expand

- (W L^{2} + 2 W Lx + W x^{2}) + 4 L W x : - W L^{2} + 2 W Lx - W x^{2}

= \frac{- W L ^{2} + 2 W Lx - W x ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- W L ^{2} + 2 W Lx - W x ^{2}}{2} = - \frac{W L ^{2}}{2} + \frac{2 W Lx}{2} - \frac{W x ^{2}}{2}

= - \frac{W L ^{2}}{2} + \frac{2 W Lx}{2} - \frac{W x ^{2}}{2}

Divide the numbers:

\frac{2}{2} = 1

= - \frac{W L ^{2}}{2} + W Lx - \frac{W x ^{2}}{2}

\frac{16}{3} - \frac{8}{3}

(x^{3} y^{4} + x) d x + (x^{4} y^{3} + y) d y

\frac{1000}{( x + 2 ) ( x + 3 ) ( x + 5 )}

2 e (e + 1) - 4 (e + 5)

\frac{50 π + 200}{( 4 + π ) ^{2}}

What is expand (-(W)(L+x)^2)/2+(2LWx) ?
The solution to expand (-(W)(L+x)^2)/2+(2LWx) is -(WL^2)/2+WLx-(Wx^2)/2