What is expand-(2x^2(15y^4+2x^4))/(25y^4) ?

The solution to expand-(2x^2(15y^4+2x^4))/(25y^4) is -(6x^2)/5-(4x^6)/(25y^4)

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expand-(2x^2(15y^4+2x^4))/(25y^4)

expand

- \frac{2 x ^{2} ( 15 y ^{4} + 2 x ^{4} )}{25 y ^{4}}

- \frac{6 x ^{2}}{5} - \frac{4 x ^{6}}{25 y ^{4}}

Solution steps

- \frac{2 x ^{2} ( 15 y ^{4} + 2 x ^{4} )}{25 y ^{4}}

Expand

2 x^{2} (15 y^{4} + 2 x^{4}) : 30 x^{2} y^{4} + 4 x^{6}

= - \frac{4 x ^{6} + 30 x ^{2} y ^{4}}{25 y ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{30 x ^{2} y ^{4} + 4 x ^{6}}{25 y ^{4}} = - (\frac{30 x ^{2} y ^{4}}{25 y ^{4}}) - (\frac{4 x ^{6}}{25 y ^{4}})

= - (\frac{30 x ^{2} y ^{4}}{25 y ^{4}}) - (\frac{4 x ^{6}}{25 y ^{4}})

Remove parentheses:

(a) = a

= - \frac{30 x ^{2} y ^{4}}{25 y ^{4}} - \frac{4 x ^{6}}{25 y ^{4}}

Cancel

\frac{30 x ^{2} y ^{4}}{25 y ^{4}} : \frac{6 x ^{2}}{5}

= - \frac{6 x ^{2}}{5} - \frac{4 x ^{6}}{25 y ^{4}}

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What is expand-(2x^2(15y^4+2x^4))/(25y^4) ?
The solution to expand-(2x^2(15y^4+2x^4))/(25y^4) is -(6x^2)/5-(4x^6)/(25y^4)