What is expand (2x+1)/((x+1)(x-1)) ?

The solution to expand (2x+1)/((x+1)(x-1)) is (2x+1)/(x^2-1)

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expand (2x+1)/((x+1)(x-1))

expand

\frac{2 x + 1}{( x + 1 ) ( x - 1 )}

\frac{2 x + 1}{x ^{2} - 1}

Solution steps

\frac{2 x + 1}{( x + 1 ) ( x - 1 )}

Expand

(x + 1) (x - 1) : x^{2} - 1

= \frac{2 x + 1}{x ^{2} - 1}

\frac{( 5 cos ( 5 x ) )}{( ( 2 x + 1 ) ^{4} ( 3 x ^{2} - 5 ) ^{3} )}

(y sec^{2} (x) + sec (x) tan (x)) d x

(x^{2} + 5) d x - (2 y - 1) d y

\frac{1 - s ^{2}}{s ^{2} ( s + 2 )}

\frac{x ^{2} - 1}{s ( x + 2 ) ( x + 3 )}

What is expand (2x+1)/((x+1)(x-1)) ?
The solution to expand (2x+1)/((x+1)(x-1)) is (2x+1)/(x^2-1)